There were some chikoos at a market. In the morning,
15 of chikoos were sold. In the afternoon, another 30 chikoos were sold. The total number of chikoos left was 4 less than
712 of the number of chikoos the market had at first.
- How many chikoos were there at first?
- What fraction of the chikoos in the market remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
5x12 = 60 u |
12x5 = 60 u |
Change 1 |
- 1x12 = - 12 u |
|
After 1 |
4x12 = 48 u |
Change 2 |
- 30 |
After 2 |
48 u - 30 |
7x5 - 4 = 35 u - 4 |
(a)
The number of chikoos at first is repeated in both comparisons. Make the number of chikoos at first. LCM of 5 and 12 is 60.
The number of chikoos in the end is the same in both comparisons.
48 u - 30 = 35 u - 4
48 u - 35 u = 30 - 4
13 u = 26
1 u = 26 ÷ 13 = 2
Number of chikoos at first
= 60 u
= 60 x 2
= 120
(b)
Number of chikoos that remained unsold
= 48 u - 30
= 48 x 2 - 30
= 96 - 30
= 66
Fraction of chikoos that remained unsold
=
66120=
1120Answer(s): (a) 120; (b)
1120