There were some starfruits at a stall. In the morning, ¹₅ of starfruits were sold. In the afternoon, another 32 starfruits were sold. The total number of starfruits left was 6 less than ⁷₁₂ of the number of starfruits the stall had at first.

1. How many starfruits were there at first?
2. What fraction of the starfruits in the stall remained unsold in the afternoon?

	Comparison 1	Comparison 2
Before	5x12 =  60 u	12x5 =  60 u
Change 1	- 1x12 = - 12 u
After 1	4x12 =  48 u
Change 2	- 32
After 2	48 u - 32	7x5 - 6 = 35 u - 6

(a)
The number of starfruits at first is repeated in both comparisons. Make the number of starfruits at first.  LCM of 5 and 12 is 60.

The number of starfruits in the end is the same in both comparisons.

48 u - 32 = 35 u - 6
48 u - 35 u = 32 - 6
13 u = 26

1 u = 26 ÷ 13 = 2

Number of starfruits at first
= 60 u
= 60 x 2
= 120

(b)
Number of starfruits that remained unsold
= 48 u - 32
= 48 x 2 - 32
= 96 - 32
= 64

Fraction of starfruits that remained unsold
= ⁶⁴₁₂₀
= ⁸₁₅

Answer(s): (a) 120; (b) ⁸₁₅