There were some lemons at a stall. In the morning,
13 of lemons were sold. In the afternoon, another 30 lemons were sold. The total number of lemons sold was 2 less than
35 of the number of lemons the stall had at first.
- How many lemons were there at first?
- What fraction of the lemons in the stall remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
3x5 =
15 u |
5x3 =
15 u |
| Change 1 |
- 1x5 =
- 5 u |
|
| After 1 |
2x5 =
10 u |
| Change 2 |
- 30 |
After 2 |
10 u - 30 |
3x3 - 2 =
9 u - 2 |
(a)
The number of lemons at first is repeated in both comparisons. Make the number of lemons at first. LCM of 3 and 5 is 15.
The number of lemons in the end is the same in both comparisons.
10 u - 30 = 9 u - 2
10 u - 9 u = 30 - 2
4 u = 32
1 u = 32 ÷ 4 = 8
Number of lemons at first
= 15 u
= 15 x 8
= 120
(b)
Number of lemons that remained unsold
= 6 u + 2
= 6 x 8 + 2
= 50
Fraction of lemons that remained unsold
=
50120=
512Answer(s): (a) 120; (b)
512 
