There were some kiwis at a stall. In the morning,
14 of kiwis were sold. In the afternoon, another 40 kiwis were sold. The total number of kiwis left was 4 less than
35 of the number of kiwis the stall had at first.
- How many kiwis were there at first?
- What fraction of the kiwis in the stall remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
4x5 = 20 u |
5x4 = 20 u |
Change 1 |
- 1x5 = - 5 u |
|
After 1 |
3x5 = 15 u |
Change 2 |
- 40 |
After 2 |
15 u - 40 |
3x4 - 4 = 12 u - 4 |
(a)
The number of kiwis at first is repeated in both comparisons. Make the number of kiwis at first. LCM of 4 and 5 is 20.
The number of kiwis in the end is the same in both comparisons.
15 u - 40 = 12 u - 4
15 u - 12 u = 40 - 4
3 u = 36
1 u = 36 ÷ 3 = 12
Number of kiwis at first
= 20 u
= 20 x 12
= 240
(b)
Number of kiwis that remained unsold
= 15 u - 40
= 15 x 12 - 40
= 180 - 40
= 140
Fraction of kiwis that remained unsold
=
140240=
712Answer(s): (a) 240; (b)
712