There were some kiwis at a market. In the morning,
14 of kiwis were sold. In the afternoon, another 20 kiwis were sold. The total number of kiwis left was 5 less than
35 of the number of kiwis the market had at first.
- How many kiwis were there at first?
- What fraction of the kiwis in the market remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change 1 |
- 1x5 =
- 5 u |
|
| After 1 |
3x5 =
15 u |
| Change 2 |
- 20 |
After 2 |
15 u - 20 |
3x4 - 5 =
12 u - 5 |
(a)
The number of kiwis at first is repeated in both comparisons. Make the number of kiwis at first. LCM of 4 and 5 is 20.
The number of kiwis in the end is the same in both comparisons.
15 u - 20 = 12 u - 5
15 u - 12 u = 20 - 5
3 u = 15
1 u = 15 ÷ 3 = 5
Number of kiwis at first
= 20 u
= 20 x 5
= 100
(b)
Number of kiwis that remained unsold
= 15 u - 20
= 15 x 5 - 20
= 75 - 20
= 55
Fraction of kiwis that remained unsold
=
55100=
1120Answer(s): (a) 100; (b)
1120 
