There were some kiwis at a supermarket. In the morning,
14 of kiwis were sold. In the afternoon, another 21 kiwis were sold. The total number of kiwis sold was 5 less than
34 of the number of kiwis the supermarket had at first.
- How many kiwis were there at first?
- What fraction of the kiwis in the supermarket remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
4x1 =
4 u |
4x1 =
4 u |
| Change 1 |
- 1x1 =
- 1 u |
|
| After 1 |
3x1 =
3 u |
| Change 2 |
- 21 |
After 2 |
3 u - 21 |
3x1 - 5 =
3 u - 5 |
(a)
The number of kiwis at first is repeated in both comparisons. Make the number of kiwis at first. LCM of 4 and 4 is 4.
The number of kiwis in the end is the same in both comparisons.
3 u - 21 = 3 u - 5
3 u - 3 u = 21 - 5
2 u = 26
1 u = 26 ÷ 2 = 13
Number of kiwis at first
= 4 u
= 4 x 13
= 52
(b)
Number of kiwis that remained unsold
= 1 u + 5
= 1 x 13 + 5
= 18
Fraction of kiwis that remained unsold
=
1852=
926Answer(s): (a) 52; (b)
926 
