There were some peaches at a shop. In the morning,
16 of peaches were sold. In the afternoon, another 21 peaches were sold. The total number of peaches sold was 9 less than
712 of the number of peaches the shop had at first.
- How many peaches were there at first?
- What fraction of the peaches in the shop remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
6x2 = 12 u |
12x1 = 12 u |
Change 1 |
- 1x2 = - 2 u |
|
After 1 |
5x2 = 10 u |
Change 2 |
- 21 |
After 2 |
10 u - 21 |
7x1 - 9 = 7 u - 9 |
(a)
The number of peaches at first is repeated in both comparisons. Make the number of peaches at first. LCM of 6 and 12 is 12.
The number of peaches in the end is the same in both comparisons.
10 u - 21 = 7 u - 9
10 u - 7 u = 21 - 9
5 u = 30
1 u = 30 ÷ 5 = 6
Number of peaches at first
= 12 u
= 12 x 6
= 72
(b)
Number of peaches that remained unsold
= 5 u + 9
= 5 x 6 + 9
= 39
Fraction of peaches that remained unsold
=
3972=
1324Answer(s): (a) 72; (b)
1324