There were some kiwis at a stall. In the morning,
16 of kiwis were sold. In the afternoon, another 35 kiwis were sold. The total number of kiwis left was 2 less than
47 of the number of kiwis the stall had at first.
- How many kiwis were there at first?
- What fraction of the kiwis in the stall remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
6x7 = 42 u |
7x6 = 42 u |
Change 1 |
- 1x7 = - 7 u |
|
After 1 |
5x7 = 35 u |
Change 2 |
- 35 |
After 2 |
35 u - 35 |
4x6 - 2 = 24 u - 2 |
(a)
The number of kiwis at first is repeated in both comparisons. Make the number of kiwis at first. LCM of 6 and 7 is 42.
The number of kiwis in the end is the same in both comparisons.
35 u - 35 = 24 u - 2
35 u - 24 u = 35 - 2
11 u = 33
1 u = 33 ÷ 11 = 3
Number of kiwis at first
= 42 u
= 42 x 3
= 126
(b)
Number of kiwis that remained unsold
= 35 u - 35
= 35 x 3 - 35
= 105 - 35
= 70
Fraction of kiwis that remained unsold
=
70126=
59Answer(s): (a) 126; (b)
59