There were some pears at a shop. In the morning,
16 of pears were sold. In the afternoon, another 24 pears were sold. The total number of pears sold was 3 less than
512 of the number of pears the shop had at first.
- How many pears were there at first?
- What fraction of the pears in the shop remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
6x2 =
12 u |
12x1 =
12 u |
| Change 1 |
- 1x2 =
- 2 u |
|
| After 1 |
5x2 =
10 u |
| Change 2 |
- 24 |
After 2 |
10 u - 24 |
5x1 - 3 =
5 u - 3 |
(a)
The number of pears at first is repeated in both comparisons. Make the number of pears at first. LCM of 6 and 12 is 12.
The number of pears in the end is the same in both comparisons.
10 u - 24 = 5 u - 3
10 u - 5 u = 24 - 3
3 u = 27
1 u = 27 ÷ 3 = 9
Number of pears at first
= 12 u
= 12 x 9
= 108
(b)
Number of pears that remained unsold
= 7 u + 3
= 7 x 9 + 3
= 66
Fraction of pears that remained unsold
=
66108=
1118Answer(s): (a) 108; (b)
1118 
