There were some lemons at a supermarket. In the morning,
16 of lemons were sold. In the afternoon, another 26 lemons were sold. The total number of lemons left was 5 less than
712 of the number of lemons the supermarket had at first.
- How many lemons were there at first?
- What fraction of the lemons in the supermarket remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
6x2 = 12 u |
12x1 = 12 u |
Change 1 |
- 1x2 = - 2 u |
|
After 1 |
5x2 = 10 u |
Change 2 |
- 26 |
After 2 |
10 u - 26 |
7x1 - 5 = 7 u - 5 |
(a)
The number of lemons at first is repeated in both comparisons. Make the number of lemons at first. LCM of 6 and 12 is 12.
The number of lemons in the end is the same in both comparisons.
10 u - 26 = 7 u - 5
10 u - 7 u = 26 - 5
3 u = 21
1 u = 21 ÷ 3 = 7
Number of lemons at first
= 12 u
= 12 x 7
= 84
(b)
Number of lemons that remained unsold
= 10 u - 26
= 10 x 7 - 26
= 70 - 26
= 44
Fraction of lemons that remained unsold
=
4484=
1121Answer(s): (a) 84; (b)
1121