There were some chikoos at a mart. In the morning,
14 of chikoos were sold. In the afternoon, another 24 chikoos were sold. The total number of chikoos left was 8 less than
712 of the number of chikoos the mart had at first.
- How many chikoos were there at first?
- What fraction of the chikoos in the mart remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
4x3 =
12 u |
12x1 =
12 u |
| Change 1 |
- 1x3 =
- 3 u |
|
| After 1 |
3x3 =
9 u |
| Change 2 |
- 24 |
After 2 |
9 u - 24 |
7x1 - 8 =
7 u - 8 |
(a)
The number of chikoos at first is repeated in both comparisons. Make the number of chikoos at first. LCM of 4 and 12 is 12.
The number of chikoos in the end is the same in both comparisons.
9 u - 24 = 7 u - 8
9 u - 7 u = 24 - 8
2 u = 16
1 u = 16 ÷ 2 = 8
Number of chikoos at first
= 12 u
= 12 x 8
= 96
(b)
Number of chikoos that remained unsold
= 9 u - 24
= 9 x 8 - 24
= 72 - 24
= 48
Fraction of chikoos that remained unsold
=
4896=
12Answer(s): (a) 96; (b)
12 
