There are 2 groups of operators in a factory. There are 3 more operators in the first group than the second group. Each operator in the first group makes 6 toys in a minute but each operator in the second group makes only 4 toys in a minute. Both groups make a total of 23040 toys in 3 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 3 |
1 u |
Value |
6 |
4 |
Total value |
6 u + 18 |
4 u |
Number of operators in first group = 1 u + 3
Number of operators in second group = 1 u
Total number of toys made
= 6 u + 18 + 4 u
= 10 u + 18
1 h = 60 min
3 h = 3 x 60 = 180 min
Total number of toys made in 1 min
= 23040 ÷ 180
= 128
10 u + 18 = 128
10 u = 128 - 18
10 u = 110
1 u = 110 ÷ 10 = 11
Number of operators in the first group
= 1 u + 3
= 11 + 3
= 14
(b)
Number of operators in the second group
= 1 u
= 11
Answer(s): (a) 14; (b) 11