There are 2 groups of operators in a factory. There are 5 more operators in the first group than the second group. Each operator in the first group makes 6 toys in a minute but each operator in the second group makes only 4 toys in a minute. Both groups make a total of 18000 toys in 2 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 5 |
1 u |
Value |
6 |
4 |
Total value |
6 u + 30 |
4 u |
Number of operators in first group = 1 u + 5
Number of operators in second group = 1 u
Total number of toys made
= 6 u + 30 + 4 u
= 10 u + 30
1 h = 60 min
2 h = 2 x 60 = 120 min
Total number of toys made in 1 min
= 18000 ÷ 120
= 150
10 u + 30 = 150
10 u = 150 - 30
10 u = 120
1 u = 120 ÷ 10 = 12
Number of operators in the first group
= 1 u + 5
= 12 + 5
= 17
(b)
Number of operators in the second group
= 1 u
= 12
Answer(s): (a) 17; (b) 12