There are 2 groups of operators in a factory. There are 8 more operators in the first group than the second group. Each operator in the first group makes 7 toys in a minute but each operator in the second group makes only 3 toys in a minute. Both groups make a total of 11520 toys in 2 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 8 |
1 u |
Value |
7 |
3 |
Total value |
7 u + 56 |
3 u |
Number of operators in first group = 1 u + 8
Number of operators in second group = 1 u
Total number of toys made
= 7 u + 56 + 3 u
= 10 u + 56
1 h = 60 min
2 h = 2 x 60 = 120 min
Total number of toys made in 1 min
= 11520 ÷ 120
= 96
10 u + 56 = 96
10 u = 96 - 56
10 u = 40
1 u = 40 ÷ 10 = 4
Number of operators in the first group
= 1 u + 8
= 4 + 8
= 12
(b)
Number of operators in the second group
= 1 u
= 4
Answer(s): (a) 12; (b) 4