There are 2 groups of operators in a factory. There are 6 more operators in the first group than the second group. Each operator in the first group makes 5 toys in a minute but each operator in the second group makes only 4 toys in a minute. Both groups make a total of 41400 toys in 5 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 6 |
1 u |
Value |
5 |
4 |
Total value |
5 u + 30 |
4 u |
Number of operators in first group = 1 u + 6
Number of operators in second group = 1 u
Total number of toys made
= 5 u + 30 + 4 u
= 9 u + 30
1 h = 60 min
5 h = 5 x 60 = 300 min
Total number of toys made in 1 min
= 41400 ÷ 300
= 138
9 u + 30 = 138
9 u = 138 - 30
9 u = 108
1 u = 108 ÷ 9 = 12
Number of operators in the first group
= 1 u + 6
= 12 + 6
= 18
(b)
Number of operators in the second group
= 1 u
= 12
Answer(s): (a) 18; (b) 12