There are 2 groups of operators in a manufacturing unit. There are 6 more operators in the first group than the second group. Each operator in the first group makes 7 toys in a minute but each operator in the second group makes only 2 toys in a minute. Both groups make a total of 15840 toys in 2 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 6 |
1 u |
Value |
7 |
2 |
Total value |
7 u + 42 |
2 u |
Number of operators in first group = 1 u + 6
Number of operators in second group = 1 u
Total number of toys made
= 7 u + 42 + 2 u
= 9 u + 42
1 h = 60 min
2 h = 2 x 60 = 120 min
Total number of toys made in 1 min
= 15840 ÷ 120
= 132
9 u + 42 = 132
9 u = 132 - 42
9 u = 90
1 u = 90 ÷ 9 = 10
Number of operators in the first group
= 1 u + 6
= 10 + 6
= 16
(b)
Number of operators in the second group
= 1 u
= 10
Answer(s): (a) 16; (b) 10