There are 2 groups of operators in a manufacturing unit. There are 7 more operators in the first group than the second group. Each operator in the first group makes 6 toys in a minute but each operator in the second group makes only 3 toys in a minute. Both groups make a total of 42300 toys in 5 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 7 |
1 u |
Value |
6 |
3 |
Total value |
6 u + 42 |
3 u |
Number of operators in first group = 1 u + 7
Number of operators in second group = 1 u
Total number of toys made
= 6 u + 42 + 3 u
= 9 u + 42
1 h = 60 min
5 h = 5 x 60 = 300 min
Total number of toys made in 1 min
= 42300 ÷ 300
= 141
9 u + 42 = 141
9 u = 141 - 42
9 u = 99
1 u = 99 ÷ 9 = 11
Number of operators in the first group
= 1 u + 7
= 11 + 7
= 18
(b)
Number of operators in the second group
= 1 u
= 11
Answer(s): (a) 18; (b) 11