There are 2 groups of operators in a plant. There are 4 more operators in the first group than the second group. Each operator in the first group makes 8 toys in a minute but each operator in the second group makes only 2 toys in a minute. Both groups make a total of 18600 toys in 5 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 4 |
1 u |
Value |
8 |
2 |
Total value |
8 u + 32 |
2 u |
Number of operators in first group = 1 u + 4
Number of operators in second group = 1 u
Total number of toys made
= 8 u + 32 + 2 u
= 10 u + 32
1 h = 60 min
5 h = 5 x 60 = 300 min
Total number of toys made in 1 min
= 18600 ÷ 300
= 62
10 u + 32 = 62
10 u = 62 - 32
10 u = 30
1 u = 30 ÷ 10 = 3
Number of operators in the first group
= 1 u + 4
= 3 + 4
= 7
(b)
Number of operators in the second group
= 1 u
= 3
Answer(s): (a) 7; (b) 3