There are 2 groups of operators in a plant. There are 6 more operators in the first group than the second group. Each operator in the first group makes 7 toys in a minute but each operator in the second group makes only 3 toys in a minute. Both groups make a total of 46080 toys in 4 hours.
- How many operators are there in the first group?
- How many operators are there in the second group?
|
First group |
Second group |
Number |
1 u + 6 |
1 u |
Value |
7 |
3 |
Total value |
7 u + 42 |
3 u |
Number of operators in first group = 1 u + 6
Number of operators in second group = 1 u
Total number of toys made
= 7 u + 42 + 3 u
= 10 u + 42
1 h = 60 min
4 h = 4 x 60 = 240 min
Total number of toys made in 1 min
= 46080 ÷ 240
= 192
10 u + 42 = 192
10 u = 192 - 42
10 u = 150
1 u = 150 ÷ 10 = 15
Number of operators in the first group
= 1 u + 6
= 15 + 6
= 21
(b)
Number of operators in the second group
= 1 u
= 15
Answer(s): (a) 21; (b) 15