Mr Peter wants to put all 28 boys and 88 girls into groups for an activity. There are more girls than boys in each group. Each group must have the same number of boys. Each group must also have the same number of girls.
- What is the greatest number of groups Mr Peter can form with these conditions?
- How many pupils are in each group?
(a)
Factors of 28 = 1, 2, 4, 7, 14, 28
Factors of 88 = 1, 2, 4, 8, 11, 22, 44, 88
Greatest number of groups Mr Peter can form
= Highest common factor of 28 and 88
= 4
(b)
Number of boys in each group = 28 ÷ 4 = 7
Number of girls in each group = 88 ÷ 4 = 22
Number of pupils in each group
= 7 + 22
= 29
Answer(s): (a) 4; (b) 29