Mr Justin wants to put all 24 girls and 51 boys into groups for an activity. There are more boys than girls in each group. Each group must have the same number of girls. Each group must also have the same number of boys.
- What is the greatest number of groups Mr Justin can form with these conditions?
- How many pupils are in each group?
(a)
Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24
Factors of 51 = 1, 3, 17, 51
Greatest number of groups Mr Justin can form
= Highest common factor of 24 and 51
= 3
(b)
Number of girls in each group = 24 ÷ 3 = 8
Number of boys in each group = 51 ÷ 3 = 17
Number of pupils in each group
= 8 + 17
= 25
Answer(s): (a) 3; (b) 25