Mr Bobby wants to put all 33 girls and 77 boys into groups for an activity. There are more boys than girls in each group. Each group must have the same number of girls. Each group must also have the same number of boys.
- What is the greatest number of groups Mr Bobby can form with these conditions?
- How many pupils are in each group?
(a)
Factors of 33 = 1, 3, 11, 33
Factors of 77 = 1, 7, 11, 77
Greatest number of groups Mr Bobby can form
= Highest common factor of 33 and 77
= 11
(b)
Number of girls in each group = 33 ÷ 11 = 3
Number of boys in each group = 77 ÷ 11 = 7
Number of pupils in each group
= 3 + 7
= 10
Answer(s): (a) 11; (b) 10