There were some rows of stools in a hall. Each row had 8 stools. When Jean brought in 12 extra stools and rearranged all the stools, there were 6 stools in each row and 3 more rows than before. How many stools were there at first?
| |
First
arrangement |
Second
arrangement |
| Number |
1 u |
1 u + 3 |
| Value |
8 |
6 |
| Total value |
8 u |
6 u + 18 |
If another 12 stools are added in the first arrangement, the total number of stools in the first arrangement and the second arrangement will be the same.
8 u + 12 = 6 u + 18
8 u - 6 u = 18 - 12
2 u = 6
1 u = 6 ÷ 2 = 3
Number of stools at first
= 8 u
= 8 x 3
= 24
Answer(s): 24
