There were some rows of tables in a school field. Each row had 10 tables. When Xylium brought in 6 extra tables and rearranged all the tables, there were 6 tables in each row and 3 more rows than before. How many tables were there at first?
|
First arrangement |
Second arrangement |
Number |
1 u |
1 u + 3 |
Value |
10 |
6 |
Total value |
10 u |
6 u + 18 |
If another 6 tables are added in the first arrangement, the total number of tables in the first arrangement and the second arrangement will be the same.
10 u + 6 = 6 u + 18
10 u - 6 u = 18 - 6
4 u = 12
1 u = 12 ÷ 4 = 3
Number of tables at first
= 10 u
= 10 x 3
= 30
Answer(s): 30