There were some rows of stools in a basketball court. Each row had 7 stools. When Kathy brought in 11 extra stools and rearranged all the stools, there were 4 stools in each row and 5 more rows than before. How many stools were there at first?
| |
First
arrangement |
Second
arrangement |
| Number |
1 u |
1 u + 5 |
| Value |
7 |
4 |
| Total value |
7 u |
4 u + 20 |
If another 11 stools are added in the first arrangement, the total number of stools in the first arrangement and the second arrangement will be the same.
7 u + 11 = 4 u + 20
7 u - 4 u = 20 - 11
3 u = 9
1 u = 9 ÷ 3 = 3
Number of stools at first
= 7 u
= 7 x 3
= 21
Answer(s): 21
