There were some rows of chairs in a canteen. Each row had 10 chairs. When Olivium brought in 8 extra chairs and rearranged all the chairs, there were 6 chairs in each row and 4 more rows than before. How many chairs were there at first?
|
First arrangement |
Second arrangement |
Number |
1 u |
1 u + 4 |
Value |
10 |
6 |
Total value |
10 u |
6 u + 24 |
If another 8 chairs are added in the first arrangement, the total number of chairs in the first arrangement and the second arrangement will be the same.
10 u + 8 = 6 u + 24
10 u - 6 u = 24 - 8
4 u = 16
1 u = 16 ÷ 4 = 4
Number of chairs at first
= 10 u
= 10 x 4
= 40
Answer(s): 40