In a club, a certain number of children can be arranged such that there are exactly 23 children per row. If the same number of children arranged in rows of 15 children each, there will be 3 more rows and 3 children left over. How many children are there altogether?
| |
First
arrangement |
Second
arrangement |
| Number |
1 u |
1 u + 3 |
| Value |
23 |
15 |
| Total value |
23 u |
15 u + 45 |
Total number of children in the first arrangement
= 1 u x 23
= 23 u
Total number of children in the second arrangement
= 15(1 u + 3)
= 15 u + 45
If 3 children were included in the second arrangement, the total number of children in the first arrangement and the second arrangement will be the same.
23 u = 15 u + 45 + 3
23 u - 15 u = 48
8 u = 48
1 u = 48 ÷ 8 = 6
Total number of children
= 23 u
= 6 x 23
= 138
Answer(s): 138
