In a club, a certain number of students can be arranged such that there are exactly 21 students per row. If the same number of students arranged in rows of 16 students each, there will be 4 more rows and 6 students left over. How many students are there altogether?
| |
First
arrangement |
Second
arrangement |
| Number |
1 u |
1 u + 4 |
| Value |
21 |
16 |
| Total value |
21 u |
16 u + 64 |
Total number of students in the first arrangement
= 1 u x 21
= 21 u
Total number of students in the second arrangement
= 16(1 u + 4)
= 16 u + 64
If 6 students were included in the second arrangement, the total number of students in the first arrangement and the second arrangement will be the same.
21 u = 16 u + 64 + 6
21 u - 16 u = 70
5 u = 70
1 u = 70 ÷ 5 = 14
Total number of students
= 21 u
= 14 x 21
= 294
Answer(s): 294
