There are a total of 760 donkeys, sheep, hens and chickens at a farm. The number of hens was 384 more than the number of donkeys. The total number of sheep and chickens was 2 times the number of donkeys.
- How many sheep and chickens were there at the farm?
- The total number of legs for all the sheep and chickens was 456. How many sheep were there in the farm?
(a)
Number of donkeys = 1 u
Number of sheep and chickens = 2 u
Number of hens = 1 u + 384
Total number of animals
= 1 u + 2 u + 1 u + 384
= 4 u + 384
4 u + 384 = 760
4 u = 760 - 384
4 u = 376
1 u = 376 ÷ 4 = 94
Number of sheep and chickens
= 2 u
= 2 x 94
= 188
(b)
Number of
sheep |
Number of
sheep' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
188
|
188 x 4 =
752 |
0
|
0
|
752
|
187
|
187 x 4 =
748 |
1
|
1 x 2 =
2 |
750
|
40
|
40 x 4 =
160 |
148
|
148 x 2=
296 |
456
|
Total number of sheep and chickens = 188
Total number of legs if all of them are sheep
= 188 x 4
= 752
Big difference in the total number of legs between the sheep and the chickens
= 752 - 456
= 296
Small difference in number of legs between one sheep and one chicken
= 4 - 2
= 2
Number of chickens
= 296 ÷ 2
= 148
Number of sheep
= 188 - 148
= 40
Answer(s): (a) 188; (b) 40
