There are a total of 648 sheep, horses, hens and chickens at a farm. The number of hens was 313 more than the number of sheep. The total number of horses and chickens was 3 times the number of sheep.
- How many horses and chickens were there at the farm?
- The total number of legs for all the horses and chickens was 566. How many horses were there in the farm?
(a)
Number of sheep = 1 u
Number of horses and chickens = 3 u
Number of hens = 1 u + 313
Total number of animals
= 1 u + 3 u + 1 u + 313
= 5 u + 313
5 u + 313 = 648
5 u = 648 - 313
5 u = 335
1 u = 335 ÷ 5 = 67
Number of horses and chickens
= 3 u
= 3 x 67
= 201
(b)
Number of
horses |
Number of
horses' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
201
|
201 x 4 =
804 |
0
|
0
|
804
|
200
|
200 x 4 =
800 |
1
|
1 x 2 =
2 |
802
|
82
|
82 x 4 =
328 |
119
|
119 x 2=
238 |
566
|
Total number of horses and chickens = 201
Total number of legs if all of them are horses
= 201 x 4
= 804
Big difference in the total number of legs between the horses and the chickens
= 804 - 566
= 238
Small difference in number of legs between one horse and one chicken
= 4 - 2
= 2
Number of chickens
= 238 ÷ 2
= 119
Number of horses
= 201 - 119
= 82
Answer(s): (a) 201; (b) 82
