There are a total of 774 pigs, buffaloes, chickens and hens at a farm. The number of chickens was 386 more than the number of pigs. The total number of buffaloes and hens was 2 times the number of pigs.
- How many buffaloes and hens were there at the farm?
- The total number of legs for all the buffaloes and hens was 504. How many buffaloes were there in the farm?
(a)
Number of pigs = 1 u
Number of buffaloes and hens = 2 u
Number of chickens = 1 u + 386
Total number of animals
= 1 u + 2 u + 1 u + 386
= 4 u + 386
4 u + 386 = 774
4 u = 774 - 386
4 u = 388
1 u = 388 ÷ 4 = 97
Number of buffaloes and hens
= 2 u
= 2 x 97
= 194
(b)
Number of
buffaloes |
Number of
buffaloes' legs |
Number of
hens |
Number of
hens' legs |
Total
|
194
|
194 x 4 =
776 |
0
|
0
|
776
|
193
|
193 x 4 =
772 |
1
|
1 x 2 =
2 |
774
|
58
|
58 x 4 =
232 |
136
|
136 x 2=
272 |
504
|
Total number of buffaloes and hens = 194
Total number of legs if all of them are buffaloes
= 194 x 4
= 776
Big difference in the total number of legs between the buffaloes and the hens
= 776 - 504
= 272
Small difference in number of legs between one buffalo and one hen
= 4 - 2
= 2
Number of hens
= 272 ÷ 2
= 136
Number of buffaloes
= 194 - 136
= 58
Answer(s): (a) 194; (b) 58
