There are a total of 732 buffaloes, sheep, chickens and geese at a farm. The number of chickens was 367 more than the number of buffaloes. The total number of sheep and geese was 3 times the number of buffaloes.
- How many sheep and geese were there at the farm?
- The total number of legs for all the sheep and geese was 586. How many sheep were there in the farm?
(a)
Number of buffaloes = 1 u
Number of sheep and geese = 3 u
Number of chickens = 1 u + 367
Total number of animals
= 1 u + 3 u + 1 u + 367
= 5 u + 367
5 u + 367 = 732
5 u = 732 - 367
5 u = 365
1 u = 365 ÷ 5 = 73
Number of sheep and geese
= 3 u
= 3 x 73
= 219
(b)
Number of
sheep |
Number of
sheep' legs |
Number of
geese |
Number of
geese' legs |
Total
|
219
|
219 x 4 =
876 |
0
|
0
|
876
|
218
|
218 x 4 =
872 |
1
|
1 x 2 =
2 |
874
|
74
|
74 x 4 =
296 |
145
|
145 x 2=
290 |
586
|
Total number of sheep and geese = 219
Total number of legs if all of them are sheep
= 219 x 4
= 876
Big difference in the total number of legs between the sheep and the geese
= 876 - 586
= 290
Small difference in number of legs between one sheep and one goose
= 4 - 2
= 2
Number of geese
= 290 ÷ 2
= 145
Number of sheep
= 219 - 145
= 74
Answer(s): (a) 219; (b) 74
