There are a total of 615 buffaloes, goats, geese and chickens at a farm. The number of geese was 330 more than the number of buffaloes. The total number of goats and chickens was 3 times the number of buffaloes.
- How many goats and chickens were there at the farm?
- The total number of legs for all the goats and chickens was 574. How many goats were there in the farm?
(a)
Number of buffaloes = 1 u
Number of goats and chickens = 3 u
Number of geese = 1 u + 330
Total number of animals
= 1 u + 3 u + 1 u + 330
= 5 u + 330
5 u + 330 = 615
5 u = 615 - 330
5 u = 285
1 u = 285 ÷ 5 = 57
Number of goats and chickens
= 3 u
= 3 x 57
= 171
(b)
Number of
goats |
Number of
goats' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
171
|
171 x 4 =
684 |
0
|
0
|
684
|
170
|
170 x 4 =
680 |
1
|
1 x 2 =
2 |
682
|
116
|
116 x 4 =
464 |
55
|
55 x 2=
110 |
574
|
Total number of goats and chickens = 171
Total number of legs if all of them are goats
= 171 x 4
= 684
Big difference in the total number of legs between the goats and the chickens
= 684 - 574
= 110
Small difference in number of legs between one goat and one chicken
= 4 - 2
= 2
Number of chickens
= 110 ÷ 2
= 55
Number of goats
= 171 - 55
= 116
Answer(s): (a) 171; (b) 116
