There are a total of 739 buffaloes, donkeys, geese and hens at a farm. The number of geese was 384 more than the number of buffaloes. The total number of donkeys and hens was 3 times the number of buffaloes.
- How many donkeys and hens were there at the farm?
- The total number of legs for all the donkeys and hens was 472. How many donkeys were there in the farm?
(a)
Number of buffaloes = 1 u
Number of donkeys and hens = 3 u
Number of geese = 1 u + 384
Total number of animals
= 1 u + 3 u + 1 u + 384
= 5 u + 384
5 u + 384 = 739
5 u = 739 - 384
5 u = 355
1 u = 355 ÷ 5 = 71
Number of donkeys and hens
= 3 u
= 3 x 71
= 213
(b)
Number of
donkeys |
Number of
donkeys' legs |
Number of
hens |
Number of
hens' legs |
Total
|
213
|
213 x 4 =
852 |
0
|
0
|
852
|
212
|
212 x 4 =
848 |
1
|
1 x 2 =
2 |
850
|
23
|
23 x 4 =
92 |
190
|
190 x 2=
380 |
472
|
Total number of donkeys and hens = 213
Total number of legs if all of them are donkeys
= 213 x 4
= 852
Big difference in the total number of legs between the donkeys and the hens
= 852 - 472
= 380
Small difference in number of legs between one donkey and one hen
= 4 - 2
= 2
Number of hens
= 380 ÷ 2
= 190
Number of donkeys
= 213 - 190
= 23
Answer(s): (a) 213; (b) 23
