There are a total of 685 buffaloes, pigs, hens and chickens at a farm. The number of hens was 333 more than the number of buffaloes. The total number of pigs and chickens was 2 times the number of buffaloes.
- How many pigs and chickens were there at the farm?
- The total number of legs for all the pigs and chickens was 508. How many pigs were there in the farm?
(a)
Number of buffaloes = 1 u
Number of pigs and chickens = 2 u
Number of hens = 1 u + 333
Total number of animals
= 1 u + 2 u + 1 u + 333
= 4 u + 333
4 u + 333 = 685
4 u = 685 - 333
4 u = 352
1 u = 352 ÷ 4 = 88
Number of pigs and chickens
= 2 u
= 2 x 88
= 176
(b)
Number of
pigs |
Number of
pigs' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
176
|
176 x 4 =
704 |
0
|
0
|
704
|
175
|
175 x 4 =
700 |
1
|
1 x 2 =
2 |
702
|
78
|
78 x 4 =
312 |
98
|
98 x 2=
196 |
508
|
Total number of pigs and chickens = 176
Total number of legs if all of them are pigs
= 176 x 4
= 704
Big difference in the total number of legs between the pigs and the chickens
= 704 - 508
= 196
Small difference in number of legs between one pig and one chicken
= 4 - 2
= 2
Number of chickens
= 196 ÷ 2
= 98
Number of pigs
= 176 - 98
= 78
Answer(s): (a) 176; (b) 78
