There are a total of 780 sheep, buffaloes, chickens and geese at a farm. The number of chickens was 400 more than the number of sheep. The total number of buffaloes and geese was 3 times the number of sheep.
- How many buffaloes and geese were there at the farm?
- The total number of legs for all the buffaloes and geese was 588. How many buffaloes were there in the farm?
(a)
Number of sheep = 1 u
Number of buffaloes and geese = 3 u
Number of chickens = 1 u + 400
Total number of animals
= 1 u + 3 u + 1 u + 400
= 5 u + 400
5 u + 400 = 780
5 u = 780 - 400
5 u = 380
1 u = 380 ÷ 5 = 76
Number of buffaloes and geese
= 3 u
= 3 x 76
= 228
(b)
Number of
buffaloes |
Number of
buffaloes' legs |
Number of
geese |
Number of
geese' legs |
Total
|
228
|
228 x 4 =
912 |
0
|
0
|
912
|
227
|
227 x 4 =
908 |
1
|
1 x 2 =
2 |
910
|
66
|
66 x 4 =
264 |
162
|
162 x 2=
324 |
588
|
Total number of buffaloes and geese = 228
Total number of legs if all of them are buffaloes
= 228 x 4
= 912
Big difference in the total number of legs between the buffaloes and the geese
= 912 - 588
= 324
Small difference in number of legs between one buffalo and one goose
= 4 - 2
= 2
Number of geese
= 324 ÷ 2
= 162
Number of buffaloes
= 228 - 162
= 66
Answer(s): (a) 228; (b) 66
