There are a total of 685 pigs, cows, chickens and hens at a farm. The number of chickens was 377 more than the number of pigs. The total number of cows and hens was 2 times the number of pigs.
- How many cows and hens were there at the farm?
- The total number of legs for all the cows and hens was 428. How many cows were there in the farm?
(a)
Number of pigs = 1 u
Number of cows and hens = 2 u
Number of chickens = 1 u + 377
Total number of animals
= 1 u + 2 u + 1 u + 377
= 4 u + 377
4 u + 377 = 685
4 u = 685 - 377
4 u = 308
1 u = 308 ÷ 4 = 77
Number of cows and hens
= 2 u
= 2 x 77
= 154
(b)
Number of
cows |
Number of
cows' legs |
Number of
hens |
Number of
hens' legs |
Total
|
154
|
154 x 4 =
616 |
0
|
0
|
616
|
153
|
153 x 4 =
612 |
1
|
1 x 2 =
2 |
614
|
60
|
60 x 4 =
240 |
94
|
94 x 2=
188 |
428
|
Total number of cows and hens = 154
Total number of legs if all of them are cows
= 154 x 4
= 616
Big difference in the total number of legs between the cows and the hens
= 616 - 428
= 188
Small difference in number of legs between one cow and one hen
= 4 - 2
= 2
Number of hens
= 188 ÷ 2
= 94
Number of cows
= 154 - 94
= 60
Answer(s): (a) 154; (b) 60
