There are a total of 660 sheep, buffaloes, geese and chickens at a farm. The number of geese was 376 more than the number of sheep. The total number of buffaloes and chickens was 2 times the number of sheep.
- How many buffaloes and chickens were there at the farm?
- The total number of legs for all the buffaloes and chickens was 496. How many buffaloes were there in the farm?
(a)
Number of sheep = 1 u
Number of buffaloes and chickens = 2 u
Number of geese = 1 u + 376
Total number of animals
= 1 u + 2 u + 1 u + 376
= 4 u + 376
4 u + 376 = 660
4 u = 660 - 376
4 u = 284
1 u = 284 ÷ 4 = 71
Number of buffaloes and chickens
= 2 u
= 2 x 71
= 142
(b)
Number of
buffaloes |
Number of
buffaloes' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
142
|
142 x 4 =
568 |
0
|
0
|
568
|
141
|
141 x 4 =
564 |
1
|
1 x 2 =
2 |
566
|
106
|
106 x 4 =
424 |
36
|
36 x 2=
72 |
496
|
Total number of buffaloes and chickens = 142
Total number of legs if all of them are buffaloes
= 142 x 4
= 568
Big difference in the total number of legs between the buffaloes and the chickens
= 568 - 496
= 72
Small difference in number of legs between one buffalo and one chicken
= 4 - 2
= 2
Number of chickens
= 72 ÷ 2
= 36
Number of buffaloes
= 142 - 36
= 106
Answer(s): (a) 142; (b) 106
