There are a total of 739 sheep, goats, geese and chickens at a farm. The number of geese was 303 more than the number of sheep. The total number of goats and chickens was 2 times the number of sheep.
- How many goats and chickens were there at the farm?
- The total number of legs for all the goats and chickens was 662. How many goats were there in the farm?
(a)
Number of sheep = 1 u
Number of goats and chickens = 2 u
Number of geese = 1 u + 303
Total number of animals
= 1 u + 2 u + 1 u + 303
= 4 u + 303
4 u + 303 = 739
4 u = 739 - 303
4 u = 436
1 u = 436 ÷ 4 = 109
Number of goats and chickens
= 2 u
= 2 x 109
= 218
(b)
Number of
goats |
Number of
goats' legs |
Number of
chickens |
Number of
chickens' legs |
Total
|
218
|
218 x 4 =
872 |
0
|
0
|
872
|
217
|
217 x 4 =
868 |
1
|
1 x 2 =
2 |
870
|
113
|
113 x 4 =
452 |
105
|
105 x 2=
210 |
662
|
Total number of goats and chickens = 218
Total number of legs if all of them are goats
= 218 x 4
= 872
Big difference in the total number of legs between the goats and the chickens
= 872 - 662
= 210
Small difference in number of legs between one goat and one chicken
= 4 - 2
= 2
Number of chickens
= 210 ÷ 2
= 105
Number of goats
= 218 - 105
= 113
Answer(s): (a) 218; (b) 113
