There are a total of 650 cows, pigs, chickens and hens at a farm. The number of chickens was 346 more than the number of cows. The total number of pigs and hens was 2 times the number of cows.
- How many pigs and hens were there at the farm?
- The total number of legs for all the pigs and hens was 490. How many pigs were there in the farm?
(a)
Number of cows = 1 u
Number of pigs and hens = 2 u
Number of chickens = 1 u + 346
Total number of animals
= 1 u + 2 u + 1 u + 346
= 4 u + 346
4 u + 346 = 650
4 u = 650 - 346
4 u = 304
1 u = 304 ÷ 4 = 76
Number of pigs and hens
= 2 u
= 2 x 76
= 152
(b)
Number of
pigs |
Number of
pigs' legs |
Number of
hens |
Number of
hens' legs |
Total
|
152
|
152 x 4 =
608 |
0
|
0
|
608
|
151
|
151 x 4 =
604 |
1
|
1 x 2 =
2 |
606
|
93
|
93 x 4 =
372 |
59
|
59 x 2=
118 |
490
|
Total number of pigs and hens = 152
Total number of legs if all of them are pigs
= 152 x 4
= 608
Big difference in the total number of legs between the pigs and the hens
= 608 - 490
= 118
Small difference in number of legs between one pig and one hen
= 4 - 2
= 2
Number of hens
= 118 ÷ 2
= 59
Number of pigs
= 152 - 59
= 93
Answer(s): (a) 152; (b) 93
