The figure, not drawn to scale, consists of a rectangle DEJK, a square EFGJ, and 2 identical quadrants DKH and EJG. DK = 9 m and JK = 2 m. Find the shaded area. (Take π = 227)
2 m
The figure, not drawn to scale, consists of a rectangle DEJK, a square EFGJ, and 2 identical quadrants DKH and EJG. DK = 9 m and JK = 2 m. Find the shaded area. (Take π = 227)
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Ischool Pte Ltd
Date:05 May 2024
Topic:
AREA PERIMETER
Question Code:
P6.AP.TL.17090730
Student:
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The figure, not drawn to scale, consists of a rectangle DEJK, a square EFGJ, and 2 identical quadrants DKH and EJG. DK = 9 m and JK = 2 m. Find the shaded area. (Take π = 227)
(2 m)
Ischool Pte Ltd
Date:
05 May 2024
Topic:
AREA PERIMETER
Question Code:
P6.AP.TL.17090730
Student:
Class:
Level:
School:
The figure, not drawn to scale, consists of a rectangle DEJK, a square EFGJ, and 2 identical quadrants DKH and EJG. DK = 9 m and JK = 2 m. Find the shaded area. (Take π = 227)
The figure, not drawn to scale, consists of a rectangle DEJK, a square EFGJ, and 2 identical quadrants DKH and EJG. DK = 9 m and JK = 2 m. Find the shaded area. (Take π = 227)
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ISchool Pte Ltd
Date:05 May 2024
Topic:AREA PERIMETER
Question Number:P6.AP.TL.17090730-A1
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