H, J and K are centres of three identical circles. The length of HJ is 5.6 m. HJ, JK and HK are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
2 m
H, J and K are centres of three identical circles. The length of HJ is 5.6 m. HJ, JK and HK are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
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Ischool Pte Ltd
Date:25 May 2024
Topic:
AREA PERIMETER
Question Code:
P6.AP.TL.17090758
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H, J and K are centres of three identical circles. The length of HJ is 5.6 m. HJ, JK and HK are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
(2 m)
Ischool Pte Ltd
Date:
25 May 2024
Topic:
AREA PERIMETER
Question Code:
P6.AP.TL.17090758
Student:
Class:
Level:
School:
H, J and K are centres of three identical circles. The length of HJ is 5.6 m. HJ, JK and HK are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
H, J and K are centres of three identical circles. The length of HJ is 5.6 m. HJ, JK and HK are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
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ISchool Pte Ltd
Date:25 May 2024
Topic:AREA PERIMETER
Question Number:P6.AP.TL.17090758-A1
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