PSLESix identical rectangular boxes can be stacked into a cupboard 0.9 m wide. Two arrangements are shown. The first arrangement in Figure A leaves a 44 cm gap at the top. The second one in Figure B leaves a 12 cm gap at the top and another gap at the side.
- In the arrangement shown in Figure B, what is the width of the gap at the side in m?
- What is the height of the cupboard in metres?
(a)
Cupboard width = 0.9 m
1 m = 100 cm
0.9 m = 90 cm
Width of one rectangle box
= 90 ÷ 2
= 45 cm
Length of the box = 1 u
Height of Figure A = 3 u + 44
Height of Figure B = 1 u + 4 x 45 + 12
The height of Figure A is equal to the height of Figure B.
3 u + 44 = 1 u + 4 x 45 + 12
2 u + 44 = 192
2 u = 192 - 44
2 u = 148
1 u = 148 ÷ 2 = 74
Width of the gap at the side of the cupboard
= 90 - 74
= 16 cm
= 0.16 m
(b)
Height of the cupboard
= 3 x 74 + 44
= 222 + 44
= 266 cm
= 2.66 m
Answer(s): (a) 0.16 m; (b) 2.66 m