The figure is made up of a right-angled triangle ABC and two semicircles with AB and BC as their diameters respectively. The two semicircles and the line AC meet at D as shown. AB = 10 m. BC = 24 m and AC = 26 m. (Take π = 3.14)

1. Find the perimeter of the shaded region. Correct the answer to 2 decimal places.
2. Find the area of the shaded region.

(a)
Circumference of Semicircle ADB
= ¹₂ x 3.14 x 10
= 15.7 m

Circumference of Semicircle CDB
= ¹₂ x 3.14 x 24
= 37.68 m

Perimeter of shaded region
= Circumference of semicircles + AC
= 15.7 m + 37.68 m + 26 m
= 79.38 m

(b)
Area of Triangle ABC
= ¹₂ x 24 x 10
= 120 m²

Area of Semicircle ADB
= ¹₂ x 3.14 x 5 x 5
= 39.25 m²

Area of Semicircle CDB
= ¹₂ x 3.14 x 12 x 12
= 226.08 m²

Area of the shaded region
= 39.25 + 226.08 - 120
= 145.33 m²

Answer(s): (a) 79.38 m; (b) 145.33 m²