The figure is made up of a right-angled triangle KLN and two semicircles with KL and LN as their diameters respectively. The two semicircles and the line KN meet at P as shown. KL = 10 m. LN = 24 m and KN = 26 m. (Take π = 3.14)
- Find the perimeter of the shaded region. Correct the answer to 2 decimal places.
- Find the area of the shaded region.
(a)
Circumference of Semicircle KPL
=
12 x 3.14 x 10
= 15.7 m
Circumference of Semicircle NPL
=
12 x 3.14 x 24
= 37.68 m
Perimeter of shaded region
= Circumference of semicircles + KN
= 15.7 m + 37.68 m + 26 m
= 79.38 m
(b)
Area of Triangle KLN
=
12 x 24 x 10
= 120 m
2 Area of Semicircle KPL
=
12 x 3.14 x 5 x 5
= 39.25 m
2 Area of Semicircle NPL
=
12 x 3.14 x 12 x 12
= 226.08 m
2 Area of the shaded region
= 39.25 + 226.08 - 120
= 145.33 m
2 Answer(s): (a) 79.38 m; (b) 145.33 m
2