The figure is made up of a big quadrant WYA a small quadrant WXB and a square XZBW. The radius of the big quadrant WYA is 35 m. The area of the big quadrant is twice the area of the small quadrant WXB. Using the calculator value of π, find the area of the shaded parts, correct to 1 decimal place.
Area of the big quadrant
= ¹₄ x π x 35 x 35 
≈ 306.25π m²

Area of the big square
= ¹₂ x 35 x 35
= 612.5 m²

Area of the small quadrant
= 306.25π ÷ 2 
≈ 153.125π m²

Area of the triangle WXB
= 612.5 ÷ 2 
= 306.25 m²

Area of the shaded part
= (306.25π - 612.5) + (153.125π - 306.25)
= 306.25π + 153.125π  - 612.5 - 306.25
= 459.375π - 918.75
≈ 524.4 m² (Correct to 1 decimal place)

Answer(s): 524.4 m²