The figure is made up of a big quadrant PRT a small quadrant PQU and a square QSUP. The radius of the big quadrant PRT is 15 cm. The area of the big quadrant is twice the area of the small quadrant PQU. Using the calculator value of π, find the area of the shaded parts, correct to 1 decimal place.
Area of the big quadrant
= ¹₄ x π x 15 x 15 
≈ 56.25π cm²

Area of the big square
= ¹₂ x 15 x 15
= 112.5 cm²

Area of the small quadrant
= 56.25π ÷ 2 
≈ 28.125π cm²

Area of the triangle PQU
= 112.5 ÷ 2 
= 56.25 cm²

Area of the shaded part
= (56.25π - 112.5) + (28.125π - 56.25)
= 56.25π + 28.125π  - 112.5 - 56.25
= 84.375π - 168.75
≈ 96.3 cm² (Correct to 1 decimal place)

Answer(s): 96.3 cm²