The figure shows a triangle MNP and 3 semicircles. If the shaded area of the semicircle, labelled K, is ¹₂ the unshaded area of the semicircle, labelled L, find the total shaded area. (Take π = 3.14)
Shaded part of Semicircle K : Unshaded part of Semicircle L : Area of shaded part of K and area of unshaded part of L
1 : 2 : 3

Area of Semicircle K
= ¹₂ x 3.14 x 7.5 x 7.5
= 88.3125 m²

Area of Semicircle L
= ¹₂ x 3.14 x 10 x 10 
= 157 m²

Area of Triangle MNP
= ¹₂ x 15 x 20
= 150 m²

Total area of the figure
= 88.3125 + 157 + 150
= 395.3125 m²

Area of the big semicircle
= ¹₂ x 3.14 x 12.5 x 12.5
= 245.3125 m²

Total area of the figure - Area of the big semicircle = 3 u

3 u = 395.3125 - 245.3125
3 u = 150 

1 u = 150 ÷ 3 = 50

Shaded part of Semicircle K
= 1 u
= 50 m²

Unshaded part of Semicircle L
= 2 u
= 2 x 50
= 100 m²

Shaded part of Semicircle L
= Area of Semicircle L - Area of unshaded part of Semicircle L
= 157 - 100
= 57 m²

Total shaded areas
= Shaded area of Semicircle K + Shaded area of Semicircle L
= 50 + 57
= 107 m²

Answer(s): 107 m²