The figure is not drawn to scale. Tank S measuring 49 cm by 46 cm by 25 cm contained 20.55 ℓ of water. Tank T measuring 40 cm by 29 cm by 35 cm contained 29 ℓ of water. Sam poured some water from Tank S into Tank T without spilling and the water level of Tank T rose to 33 cm. What was the height of water level left in Tank S?
1 ℓ = 1000 cm³
29 ℓ = 29000 cm³
20.55 ℓ = 20.55 x 1000 = 20550 cm³

Height of water in Tank T at first
= 29000 ÷ 40 ÷ 29
= 25 cm

Increase in the height of water in Tank T
= 33 - 25
= 8 cm

Volume of water poured into Tank T
= 40 x 29 x 8
= 9280 cm³ 

Volume of water left in Tank S
= 20550 - 9280
= 11270 cm³ 

Height of water left in Tank S
= 11270 ÷ 49 ÷ 46
= 5 cm

Answer(s): 5 cm