Container P and Q are identical containers with the same base area and height. Container P is filled to the brim with water while Container Q is empty. After 276 cm³ of water from Container P is poured into Container Q, the depth of water in Container Q is ¹₂ the depth of water in Container P. If the height of Container Q is 46 cm, what is the base area of Container Q?
The depth of water is proportional to the volume of water.

After water from Container P is poured into Container Q:

Volume of water in Container P : Volume of water in Container Q
 2 : 1

1 u = 276

Total volume of Container Q
= 2 u + 1 u
= 3 u
= 3 x 276
= 828 cm³

Base area of Container Q
= 828 ÷ 46
= 18 cm²

Answer(s): 18 cm²